2^2x+3=65(2^x-2)+122

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Solution for 2^2x+3=65(2^x-2)+122 equation: 



2^2x+3=65(2^x-2)+122

We move all terms to the left:

2^2x+3-(65(2^x-2)+122)=0



We calculate terms in parentheses: -(65(2^x-2)+122), so:

65(2^x-2)+122

We multiply parentheses

130x-130+122

We add all the numbers together, and all the variables

130x-8

Back to the equation:

-(130x-8)



We get rid of parentheses

2^2x-130x+8+3=0

We add all the numbers together, and all the variables

-130x+2^2x+11=0

We move all terms containing x to the left, all other terms to the right

-130x+2^2x=-11

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